Hi,
This is possible. I have updated the original article with Example 2. Simply review Example 2, follow the instructions and let me know if that solves your issue.

var arr= [“test one”, “test two”, “test three”];

if (arr.indexOf(‘two’) != -1)
{
alert(‘Value exists in array.’);
}

Hi Tahir,
I did find some mistakes with your code. You have corrected the first issue and that was of the double “i”. Next, you are declaring array as var arr, but you are using an incorrect array name (temp). You don’t have a temp array with values in it. You have an “arr” array. Other than that it should work. I fixed the entire code. You can find it below:
var srch = 'val four';
var arr = ['val one', 'val two', 'val three', 'val four', 'val five'];

for(var i = 0; i<= arr.length; i++) { if(srch == arr[i]) { alert('this value is in array'); } else { alert('this value is not in array'); } }
My code above it works for me. So try out the above code & let me know how it goes.

this is

if(srch == temp[i])


now please help


var srch = 'val four';
var arr = ['val one', 'val two', 'val three', 'val four', 'val five'];
for(var i = 0; i <= arr.length; i++)
{
if(srch == temp[ii])
{
alert('this value is in array');
}
else {
alert('this value is not in array');
}

please tell me that why this is not working..
thanks again